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You want to be able to access the largest element in a stack.
You've already implemented this Stackclass:
class Stack {
constructor() {
// Initialize an empty stack
this.items = [];
}
// Push a new item onto the stack
push(item) {
this.items.push(item);
}
// Remove and return the last item
pop() {
// If the stack is empty, return null
// (It would also be reasonable to throw an exception)
if (!this.items.length) {
return null;
}
return this.items.pop();
}
// Returns the last item without removing it
peek() {
if (!this.items.length) {
return null;
}
return this.items[this.items.length - 1];
}
}
Use yourStackclass to implement a newclassMaxStack with a methodgetMax that returns the largest element in the stack.getMax should not remove the item.
Your stacks will contain only integers.
What if we push several items in increasing numeric order (like 1, 2, 3, 4...), so that there is a new max after each push? What if we then pop each of these items off, so that there is a new max after each pop? Your algorithm shouldn't pay a steep cost in these edge cases.
You should be able to get a runtime of for push, pop, and getMax.
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